(3x^2-18x+24)/(x-4)

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Solution for (3x^2-18x+24)/(x-4) equation:


D( x )

x-4 = 0

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

x in (-oo:4) U (4:+oo)

(3*x^2-(18*x)+24)/(x-4) = 0

(3*x^2-18*x+24)/(x-4) = 0

3*x^2-18*x+24 = 0

3*(x^2-6*x+8) = 0

x^2-6*x+8 = 0

DELTA = (-6)^2-(1*4*8)

DELTA = 4

DELTA > 0

x = (4^(1/2)+6)/(1*2) or x = (6-4^(1/2))/(1*2)

x = 4 or x = 2

3*(x-2)*(x-4) = 0

3*(x-2) = 0

x-2 = 0 // + 2

x = 2

x = 2

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